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प्रश्न
Explain why the inductance of two coils connected in parallel is less than the inductance of either coil.
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उत्तर १
- For a parallel combination of two coils, the current through each parallel inductor is a fraction of the total current and the voltage across each parallel inductor is the same.
- As a result, a change in total current will result in less voltage dropped across the parallel array than for any one of the individual inductors.
- There will be less voltage drop across parallel inductors for a given rate of change in current than for any of the individual inductors.
- Less voltage for the same rate of change in current results in less inductance.
- Thus, the total inductance of two coils is less than the inductance of either coil.
उत्तर २
When two inductors with inductances L1 and L2 are connected in parallel, the equivalent inductance is given by
`1/"L"_"equivalent" = 1/"L"_1 + 1/"L"_2`
which is less than the individual inductance value L1 and L2.
As a result, the inductance of two parallel coils is smaller than the inductance of either coil.
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संबंधित प्रश्न
Explain the phenomenon of self induction
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(a) magnetic field at the centre
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(c) self-inductance of the solenoid
(d) rate of Joule heating.
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Answer the following question.
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What does \[L\] represent?
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What does \[\Phi_B\] represent, and what is its SI unit?
What does \[I\] represent, and what is its SI unit?
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For an air (or vacuum) core, which permeability is used in the solenoid derivation?
What is the magnetic field inside a long air-core solenoid?
What is the magnetic flux through one turn of the long solenoid?
Before substituting \[N=nl\], what is the total flux linkage through all \[N\] turns?
What is the self-inductance of a long air-core solenoid?
How does a magnetic core of relative permeability \[\mu_r\] change the solenoid self-inductance expression?
In which field is the energy of an inductor stored?
Which energy expression and field belong to a capacitor?
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