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An Average Emf of 20 V is Induced in an Inductor When the Current in It is Changed from 2.5 a in One Direction to the Same Value in the Opposite Direction in 0.1 S.

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प्रश्न

An average emf of 20 V is induced in an inductor when the current in it is changed from 2.5 A in one direction to the same value in the opposite direction in 0.1 s. Find the self-inductance of the inductor.

योग
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उत्तर

Let the self-inductance of the inductor be L.

Average emf induced in the inductor, V = 20 V

Change in current, di = i2 − i1 = 2.5 − (−2.5) = 5 A

Time taken for the change, dt = 0.1 s

The voltage induced in the inductor is given by

\[V = L\frac{di}{dt}\]

\[ \Rightarrow 20 = L\left( \frac{5}{0 . 1} \right)\]

\[ \Rightarrow 20 = L \times 50\]

\[ \Rightarrow L = \frac{20}{50} = \frac{4}{10} = 0 . 4 H\]

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अध्याय 38: Electromagnetic Induction - Exercises [पृष्ठ ३१२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 38 Electromagnetic Induction
Exercises | Q 66 | पृष्ठ ३१२

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