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प्रश्न
Explain the following SQL function using a suitable example.
TRIM()
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उत्तर
TRIM(): It removes the leading and trailing spaces from the given string.
Example: SELECT TRIM(‘ Welcome world ‘);
Output: Welcome world
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संबंधित प्रश्न
Which of the following belongs to an "aggregate function"?
Consider the table STUDENT given below:
| RollNo | Name | Class | DOB | Gender | City | Marks |
| 1 | Anand | XI | 6/6/97 | M | Agra | 430 |
| 2 | Chetan | XII | 7/5/94 | M | Mumbai | 460 |
| 3 | Geet | XI | 6/5/97 | F | Agra | 470 |
| 4 | Preeti | XII | 8/8/95 | F | Mumbai | 492 |
| 5 | Saniyal | XII | 8/10/95 | M | Delhi | 360 |
| 6 | Maakhiy | XI | 12/12/94 | F | Dubai | 256 |
| 7 | Neha | X | 8/12/95 | F | Moscow | 324 |
| 8 | Nishant | X | 12/6/95 | M | Moscow | 429 |
State the command that will give the output as:
| Name |
| Anand |
| Chetan |
| Geet |
| Preeti |
(i) select Name from student where Class ='XI' and Class='XII';
(ii) select name from student where not Class='XI' and Class='XII';
(iii) select name from student where City="Agra" or City="Mumbai";
(iv) select name from student where City in("Agra", "Mumbai");
Choose the correct option:
Consider the table STUDENT given below:
| RollNo | Name | Class | DOB | Gender | City | Marks |
| 1 | Anand | XI | 6/6/97 | M | Agra | 430 |
| 2 | Chetan | XII | 7/5/94 | M | Mumbai | 460 |
| 3 | Geet | XI | 6/5/97 | F | Agra | 470 |
| 4 | Preeti | XII | 8/8/95 | F | Mumbai | 492 |
| 5 | Saniyal | XII | 8/10/95 | M | Delhi | 360 |
| 6 | Maakhiy | XI | 12/12/94 | F | Dubai | 256 |
| 7 | Neha | X | 8/12/95 | F | Moscow | 324 |
| 8 | Nishant | X | 12/6/95 | M | Moscow | 429 |
State the command to display the average marks scored by students of each gender who are in class XI?
(i) Select Gender, avg(Marks) from STUDENT where Class= "XI" group by Gender;
(ii) Select Gender, avg(Marks) from STUDENT group by Gender where Class="XI";
(iii) Select Gender, avg(Marks) group by Gender from STUDENT having Class="XI";
(iv) Select Gender, avg(Marks) from STUDENT group by Gender having Class = "XI";
Choose the correct option:
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s="welcome2cs"
n = len(s)
m=""
for i in range(0, n):
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m = m +s[i].upper()
elif (s[i] >= 'n' and s[i] <= 'z'):
m = m +s[i-1]
elif (s[i].isupper()):
m = m + s[i].lower()
else:
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