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प्रश्न
Write suitable SQL query for the following:
Display 7 characters extracted from the 7th left character onwards from the string ‘INDIA SHINING’.
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उत्तर
select mid('INDIA SHINING',7,7);
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संबंधित प्रश्न
______ is used to get a specified day of the month for a given date.
Which method is used to get the row-id of the last modified row?
Which of the following belongs to an "aggregate function"?
The MAX () function finds the
Consider the table STUDENT given below:
| RollNo | Name | Class | DOB | Gender | City | Marks |
| 1 | Anand | XI | 6/6/97 | M | Agra | 430 |
| 2 | Chetan | XII | 7/5/94 | M | Mumbai | 460 |
| 3 | Geet | XI | 6/5/97 | F | Agra | 470 |
| 4 | Preeti | XII | 8/8/95 | F | Mumbai | 492 |
| 5 | Saniyal | XII | 8/10/95 | M | Delhi | 360 |
| 6 | Maakhiy | XI | 12/12/94 | F | Dubai | 256 |
| 7 | Neha | X | 8/12/95 | F | Moscow | 324 |
| 8 | Nishant | X | 12/6/95 | M | Moscow | 429 |
State the command to display the average marks scored by students of each gender who are in class XI?
(i) Select Gender, avg(Marks) from STUDENT where Class= "XI" group by Gender;
(ii) Select Gender, avg(Marks) from STUDENT group by Gender where Class="XI";
(iii) Select Gender, avg(Marks) group by Gender from STUDENT having Class="XI";
(iv) Select Gender, avg(Marks) from STUDENT group by Gender having Class = "XI";
Choose the correct option:
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Table: Teacher
| T_ID | Name | Age | Department | Date_of_join | Salary | Gender |
| 1 | Arunan | 34 | Computer Sc | 2019-01-10 | 12000 | M |
| 2 | Saman | 31 | History | 2017-03-24 | 20000 | F |
| 3 | Randeep | 32 | Mathematics | 2020-12-12 | 30000 | M |
| 4 | Samira | 35 | History | 2018-07-01 | 40000 | F |
| 5 | Raman | 42 | Mathematics | 2021-09-05 | 25000 | M |
| 6 | Shyam | 50 | History | 2019-06-27 | 30000 | M |
| 7 | Shiv | 44 | Computer Sc | 2019-02-25 | 21000 | M |
| 8 | Shalakha | 33 | Mathematics | 2018-07-31 | 20000 | F |
Table: Placement
| P_ID | Department | Place |
| 1 | History | Ahmedabad |
| 2 | Mathematics | Jaipur |
| 3 | Computer Sc | Nagpur |
- SELECT Department, avg(salary) FROM Teacher GROUP BY Department;
- SELECT MAX(Date_of_Join), MIN(Date_of_Join) FROM Teacher;
- SELECT Name, Salary, T.Department, Place FROM Teacher T, Placement P WHERE T.Department = P.Department AND Salary>20000;
- SELECT Name, Place FROM Teacher T, Placement P WHERE Gender = ’F’ AND T.Department = P.Department;
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Write suitable SQL query for the following:
Round off the value 23.78 to one decimal place.
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Display the remainder of 100 divided by 9.
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