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प्रश्न
Explain the bonding in methane molecule using electron dot structure.
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उत्तर
Formation of methane molecule – Non-polar covalent compound:
| Atom | Electronic configuration | Nearest noble gas | To attain stable electronic the configuration of nearest noble gas |
| Carbon | `""_6^12C[2,4]` | Neon [2,8] | Carbon needs four electrons to complete the octet |
| Hydrogen | `""_1^1H[1]` | Helium [2] | Hydrogen needs one electron to complete the duplet |
One atom of carbon shares four electron pairs, one with each of the four atoms of
hydrogen.
 |
|
| Before combination (4 [H] and 1 [C] atom) |
After combination (CH4 – Methane molecule) |
संबंधित प्रश्न
State the type of bonding in the following molecule.
Water
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State the type of bonding in the following molecule.
Methane
Choose the correct answer from the options given below
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An element L consists of molecules.
What type of bonding is present in the particles that make up L?
What is the difference between :
Ionic compounds and covalent compounds
Give an example for each of the following statement.
Formation of coordinate covalent bond between NH3 ➝ BF3 molecules
Which of the following are correct structural isomers of butane?
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}|\phantom{.....}|\\
\ce{H}\ce{H-C-H}\ce{H}\\
|\\
\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}\backslash\phantom{..}|\\
\phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
\phantom{.......}|\\
\phantom{.......}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\\
\end{array}\]
The table shows the electronic structures of four elements.
| Element | Electronic Structure |
| P | 2, 6 |
| Q | 2, 8, 1 |
| R | 2, 8, 7 |
| S | 2, 8, 8 |
- Identify which element(s) will form covalent bonds with carbon.
- “Carbon reacts with an element in the above table to form several compounds.” Give suitable reason.
