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Electrons Are Emitted by a Hot Filament and Are Accelerated by an Electric Field, as Shown in the Figure. the Two Stops at the Left Ensure that the Electron Beam Has a Uniform Cross-section.

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प्रश्न

Electrons are emitted by a hot filament and are accelerated by an electric field, as shown in the figure. The two stops at the left ensure that the electron beam has a uniform cross-section.

विकल्प

  • The speed of the electrons is more at B than at A

  • The electric current is from left to right

  • The magnitude of the current is larger at B than at A

  • The current density is more at B than at A

MCQ
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उत्तर

The speed of the electrons is more at B than at A

 

Let the potentials at A and B be VA  and VB.

As potential,

\[E = - \frac{dV}{dr}\]

potential increases in the direction opposite to the direction of the electric field.

Thus, VA < VB

Potential energy of the electrons at points A and B:-

UA = -eVA

UB = -eVB

Thus, UA > UB

Let the kinetic energy of an electron at points A and B be Kand KB respectively.

Applying the principle of conservation of mechanical energy, we get:-

UA  + KA  = UB  + KB

As, UA > UB,

KA < KB

Therefore, the speed of the electrons is more at B than at A.

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अध्याय 32: Electric Current in Conductors - MCQ [पृष्ठ १९७]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 32 Electric Current in Conductors
MCQ | Q 1 | पृष्ठ १९७

संबंधित प्रश्न

Define the term drift velocity.


What is its relation with relaxation time?


Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 2.5 × 10−7 m2 carrying a current of 1.8 A. Assume the density of conduction electrons to be 9 × 1028 m−3.


Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 2·5 × 10−7 m2 carrying a current of 2·7 A. Assume the density of conduction electrons to be 9 × 1028 m−3


A wire whose cross-sectional area is increasing linearly from its one end to the other, is connected across a battery of V volts.
Which of the following quantities remain constant in the wire?
(a) drift speed
(b) current density
(c) electric current
(d) electric field

On the basis of electron drift, derive an expression for resistivity of a conductor in terms of number density of free electrons and relaxation time. On what factors does resistivity of a conductor depend?


Why alloys like constantan and manganin are used for making standard resistors?


Explain the term ‘drift velocity’ of electrons in conductor. Hence obtain the expression for the current through a conductor in terms of ‘drift velocity’. 


When electrons drift in a metal from lower to higher potential, does it mean that all the free electrons of the metal are moving in the same direction?


Consider the following statements.
(A) Free-electron density is different in different metals.
(B) Free-electron density in a metal depends on temperature.
Seebeck Effect is caused _____________ .


Consider the following statements.
(A) Free-electron density is different in different metals.
(B) Free-electron density in a metal depends on temperature.

Peltier Effect is caused _______________ .


Metals are good conductor of heat than insulator because


Amount of charge in coulomb required to deposit one gram equivalent of substance by electrolysis is:-


An electric bulb.is rated 220 v and 100 watt power consumed by it when operated on 'no volt is:-


  1. Consider circuit in figure. How much energy is absorbed by electrons from the initial state of no current (ignore thermal motion) to the state of drift velocity?
  2. Electrons give up energy at the rate of RI2 per second to the thermal energy. What time scale would one associate with energy in problem (a)? n = no of electron/volume = 1029/m3, length of circuit = 10 cm, cross-section = A = (1mm)2


Explain how free electrons in a metal at constant temperature attain an average velocity under the action of an electric field. Hence, obtain an expression for it.


Two conductors, made of the same material have equal lengths but different cross-sectional areas A1 and A2 (A1 > A2). They are connected in parallel across a cell. Show that the drift velocities of electrons in two conductors are equal.


The drift velocity of electrons in a conductor connected to a battery is given by vd = `(−"eE" τ)/"m"`. Here, e is the charge of the electron, E is the electric field, τ is the average time between collisions and m is the mass of the electron.

Based on this, answer the following:

  1. How does the drift velocity change with a change in the potential difference across the conductor?
  2. A copper wire of length 'l' is connected to a source. If the copper wire is replaced by another copper wire of the same area of cross-section but of length '4l', how will the drift velocity change? Explain your answer.

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