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The number density of free electrons in a copper conductor is 8.5 × 1028 m−3. How long does an electron take to drift from one end of a wire 3.0 m long to its other end? - Physics

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प्रश्न

The number density of free electrons in a copper conductor is 8.5 × 1028 m−3. How long does an electron take to drift from one end of a wire 3.0 m long to its other end? The area of cross-section of the wire is 2.0 × 10−6 m2 and it is carrying a current of 3.0 A.

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उत्तर

Number density of free electrons in a copper conductor, n = 8.5 × 1028 m−3

Length of the copper wire, l = 3.0 m

Area of cross-section of the wire, A = 2.0 × 10−6 m2

Current carried by the wire, I = 3.0 A, which is given by the relation,

I = nAeVd

Where,

e = Electric charge = 1.6 × 10−19 C

Vd = Drift velocity =`"Length of the wire (l)"/"Time taken to cover l(t)"`

I = `"nAe""l"/"t"`

t = `"nAel"/"I"`

= `(3 xx 8.5 xx 10^28 xx 2 xx 10^-6 xx 1.6 xx 10^-19)/3.0`

= 2.7 × 104 s

Therefore, the time it takes for an electron to drift from one end of the wire to the other is 2.7 × 104 s.

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अध्याय 3: Current Electricity - EXERCISES [पृष्ठ १०६]

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एनसीईआरटी Physics [English] Class 12
अध्याय 3 Current Electricity
EXERCISES | Q 3.9 | पृष्ठ १०६

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