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Does the Specific Heat Depend Upon the Temperature?

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प्रश्न

Does the specific heat depend upon the temperature?
एक पंक्ति में उत्तर
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उत्तर

No, specific heat does not depend on temperature. It is constant for a substance.
 
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अध्याय 5: Heat - Exercise 5.2 i [पृष्ठ २४१]

APPEARS IN

फ्रैंक Physics Part 2 [English] Class 10 ICSE
अध्याय 5 Heat
Exercise 5.2 i | Q 7 | पृष्ठ २४१

संबंधित प्रश्न

In an experiment on the specific heat of a metal, a 0.20 kg block of the metal at 150 °C is dropped in a copper calorimeter (of water equivalent 0.025 kg) containing 150 cm3 of water at 27 °C. The final temperature is 40 °C. Compute the specific heat of the metal. If heat losses to the surroundings are not negligible, is your answer greater or smaller than the actual value for the specific heat of the metal?


A refrigerator converts 100 g of water at 20°C to ice at -10°C in 35 minutes. Calculate the average rate of heat extraction in terms of watts.

Given: Specific heat capacity of ice = 2.1 J g-1°C-1

Specific heat capacity of water = 4.2 J g-1°C-1

Specific latent heat of fusion of ice = 336 J g-1


50 g of metal piece at 27°C requires 2400 J of heat energy so as to attain a temperature of 327°C . Calculate the specific heat capacity of the metal.


What is the specific heat capacity of boiling water?


m kg of a substance of specific heat capacity s J/kg °C is heated so that its temperature rises from θ1°C to θ2°C. Write down the expression for the heat Q supplied.


Describe a method to determine the specific heat capacity of a solid (say, a piece of copper).


Explain how heat capacity of a solid can be determined by the method of mixture.


A diatomic gas undergoes adiabatic change. Its pressure 'P' and temperature 'T' are related as p ∝ Tx, where x is ______.


Match the following

1. Specific heat capacity a. Dewar bottle
2. Calorimeter b. Lavoisier and Simon
3. Vacuum flask c. J Kg-1 K-1
4. Ice – calorimeter d. Heat capacity

We would like to make a vessel whose volume does not change with temperature (take a hint from the problem above). We can use brass and iron `(β_(vbrass) = (6 xx 10^(–5))/K and β_(viron) = (3.55 xx 10^(–5))/K)` to create a volume of 100 cc. How do you think you can achieve this.


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