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Divide. Write the quotient and the remainder. (21x^4 − 14x^2 + 7x) ÷ 7x^3 - Mathematics

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प्रश्न

Divide. Write the quotient and the remainder.

(21x4 − 14x2 + 7x) ÷ 7x3

योग
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उत्तर

(21x4 − 14x2 + 7x) ÷ 7x3

= `(21 x^4 - 14 x^2 + 7x)/(7 x^3)`

= `(7 x^3 xx 3x - 14 x^2 + 7 x)/(7 x^3)`

= `(7 x^3 xx 3x)/(7 x^3) + (-14 x^2 + 7 x)/(7 x^3)`

= `3 x + (-14 x^2 + 7 x)/(7 x^3)`

So, quotient = 3x and remainder = −14x2 + 7x

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अध्याय 10: Division of Polynomials - Practice Set 10.1 [पृष्ठ ६४]

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बालभारती Mathematics [English] Standard 8 Maharashtra State Board
अध्याय 10 Division of Polynomials
Practice Set 10.1 | Q 8 | पृष्ठ ६४
बालभारती Mathematics Integrated [English] Standard 8 Maharashtra State Board
अध्याय 10 Division of Polynomials
Practice Set 10.1 | Q 1. (8) | पृष्ठ ३९
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