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प्रश्न
Divide. Write the quotient and the remainder.
(21x4 − 14x2 + 7x) ÷ 7x3
बेरीज
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उत्तर
(21x4 − 14x2 + 7x) ÷ 7x3
= `(21 x^4 - 14 x^2 + 7x)/(7 x^3)`
= `(7 x^3 xx 3x - 14 x^2 + 7 x)/(7 x^3)`
= `(7 x^3 xx 3x)/(7 x^3) + (-14 x^2 + 7 x)/(7 x^3)`
= `3 x + (-14 x^2 + 7 x)/(7 x^3)`
So, quotient = 3x and remainder = −14x2 + 7x
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