Question

Divide. Write the quotient and the remainder.

 (2y³ + 4y² + 3) ÷ 2y²

Answer 1

 (2y³ + 4y² + 3) ÷ 2y²

= \[\frac{2 y^3 + 4 y^2 + 3}{2 y^2}\] 

= \[\frac{2 y^2 \left( y + 2 \right) + 3}{2 y^2}\] 

= \[\frac{2 y^2 \left( y + 2 \right)}{2 y^2} + \frac{3}{2 y^2}\] 

= \[\left( y + 2 \right) + \frac{3}{2 y^2}\]

So, quotient = \[\left(y + 2 \right)\] and remainder = 3