Question

Divide. Write the quotient and the remainder.

(6x⁵ − 4x⁴ + 8x³ + 2x²) ÷ 2x²

Answer 1

(6x⁵ − 4x⁴ + 8x³ + 2x²) ÷ 2x²

= \[\frac{6 x^5 - 4 x^4 + 8 x^3 + 2 x^2}{2 x^2}\] 

= \[\frac{2 x^2 \left( 3 x^3 - 2 x^2 + 4x + 1 \right)}{2 x^2}\] 

= \[3 x^3  - 2 x^2  + 4x + 1\]

So, quotient = \[3 x^3  - 2 x^2  + 4x + 1\] and remainder = 0