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Differentiate the following w.r.t. x: log (cos e^x)

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प्रश्न

Differentiate the following w.r.t. x:

log (cos ex)

योग
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उत्तर

Let, y = log (cos ex)

Differentiating both sides with respect to x,

`dy/dx= d/dx log (cos e^x)`

= `1/(cos e^x) d/dx (cos e^x)`

= `1/(cos e^x) (- sin e^x) d/dx e^x`

= `-(sin e^x)/(cos e^x) * e^x`

= −ex tan ex

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity and Differentiability - Exercise 5.4 [पृष्ठ १७४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.4 | Q 5 | पृष्ठ १७४

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