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Differentiate the following w.r.t. x: √e^√x, x > 0

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प्रश्न

Differentiate the following w.r.t. x:

`sqrt(e^(sqrtx))`, x > 0

योग
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उत्तर

Let, y = `sqrt(e^(sqrtx))`

Differentiating both sides with respect to x,

`dy/dx = d/dx (e^(sqrtx))^(1/2)`

= `1/2 (e^(sqrtx))^(1/2 - 1) d/dx e^(sqrtx)`

= `1/2 (e^(sqrtx))^(-1/2) e^(sqrtx) d/dx x^(1/2)`

= `1/2 (e^(sqrtx))^(-1/2) e^(sqrtx) 1/2 x^(-1/2)`

= `1/4 1/(sqrt(e^(sqrtx))) e^(sqrtx) 1/sqrtx`

= `1/4 e^(sqrtx)/(sqrt(x. e^(sqrtx)))`, x > 0

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity and Differentiability - Exercise 5.4 [पृष्ठ १७४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.4 | Q 7 | पृष्ठ १७४

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