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Differentiate the following w.r.t. x: sin (tan^–1 e^–x)

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प्रश्न

Differentiate the following w.r.t. x: 

sin (tan–1 e–x)

योग
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उत्तर

Let, y = sin (tan–1 e–x)

Differentiating both sides with respect to x,

`dy/dx = d/dx sin(tan^-1 e^(-x))`

= `cos (tan^-1 e^-x) d/dx  tan^-1 e^-x`

= `cos (tan^-1 e^-x) 1/(1 + (e^-x)^2) d/dx (e^-x)`

= `cos (tan^-1 e^-x) 1/(1 + e^(-2x)) (e^-x) d/dx (-x)`

= `cos (tan^-1 e^-x) e^-x/(1 + e^(-2x)) (-1)`

= `-(e^-x cos (tan^-1 e^-x))/(1 + e^(-2x))`

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अध्याय 5: Continuity and Differentiability - Exercise 5.4 [पृष्ठ १७४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.4 | Q 4 | पृष्ठ १७४

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