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प्रश्न
Derive the relation a sin θ = λ for the first minimum of the diffraction pattern produced due to a single slit of width ‘a’ using light of wavelength λ.
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उत्तर
sin θ = `(BE)/(AB)`
BE = AB sin θ AB = a
BE = a sin θ
for first minima at P
path difference BE = λ
a sin θ = λ

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संबंधित प्रश्न
A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen. Find the width of the slit.
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Draw the intensity pattern for double slit interference.
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Deduce, with the help of Young's arrangement to produce interference pattern, an expression for the fringe width.
A parallel beam of light of 450 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1.5 m away. It is observed that the first minimum is at a distance of 3 mm from the centre of the screen. Calculate the width of the slit.
Which electric bulb is required for the observation?
Which items are optional in the apparatus?
What pattern appears when the bulb filament is viewed through the slit?
What fringe pattern is observed through a red colour filter?
Why is the fringe pattern wider with a red colour filter?
