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प्रश्न
Derive the relation a sin θ = λ for the first minimum of the diffraction pattern produced due to a single slit of width ‘a’ using light of wavelength λ.
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उत्तर
sin θ = `(BE)/(AB)`
BE = AB sin θ AB = a
BE = a sin θ
for first minima at P
path difference BE = λ
a sin θ = λ
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संबंधित प्रश्न
A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen. Find the width of the slit.
State differences between interference and diffraction patterns.
Using the monochromatic light of same wavelength in the experimental set-up of the diffraction pattern as well as in the interference pattern where the slit separation is 1 mm, 10 interference fringes are found to be within the central maximum of the diffraction pattern. Determine the width of the single slit, if the screen is kept at the same distance from the slit in the two cases.
Derive the relation a sin θ = λ for the first minimum of the diffraction pattern produced due to a single slit of width 'a' using light of wavelength λ.
Which items are used to form the narrow, uniform slit?
Which items are optional in the apparatus?
How should the slit be oriented relative to the filament of the lit glass bulb?
What pattern appears when the bulb filament is viewed through the slit?
What happens to the bands when the slit width is narrowed?
What is visible with white light and no filter?
