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In Young’S Double Slit Experiment, the Slits Are Separated by 0.5 Mm and Screen is Placed 1.0 M Away from the Slit. It is Found that the 5th Bright Fringe is at a Distance of 4.13 Mm

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प्रश्न

In Young’s double slit experiment, the slits are separated by 0.5 mm and screen is placed 1.0 m away  from the slit. It is found that the 5th bright fringe is at a distance of 4.13 mm from the 2nd dark fringe.  Find the wavelength of light used.  

संक्षेप में उत्तर
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उत्तर

Given d =  0.5mm
D = 1.0m 

5th bright `x_n = ( n lambda D ) / d`

`x_5 = 5 ( lambda D) /d`

2nd dark `x_m = (2m-1) (lambdaD)/(2d)`

`5(lambdaD)/(d) = (3 lambdaD)/(2d) = 4.13 xx 10^(-3) ⇒ ( 7lambdaD)/(2d) = 4.13  xx 10^(-3)`

`(7lambda xx 1)/(2 xx5 xx10^(-4)) = 4.13 xx 10^(-3)    lambda = (2 xx 4.13 xx 10^(-3) xx 5 xx 10^(-4))/7`

`lambda = 5.9 xx 10^(-7) m`

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2018-2019 (March) 55/3/3

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