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Define the mean chart

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प्रश्न

Define the mean chart

योग
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उत्तर

The mean chart `(bar"X"  "chart")` is used to show, the quality average of the samples taken from the given process.

The `bar"X"` charts are usually required for decision making to accept or reject the process.

Procedure for `bar"X"`

i. Let X1, X2, X3, etc. be the samples selected each containing “n” observations usually (n = 4.5 or 6)

ii. Calculate mean for each samples `bar"X"_1,  bar"X"_2,  bar"X"_3`, ......... by using `bar"X"_"i" = (sum"X"_"i")/"n"`, i = 1, 2, 3, 4, ….

Where `sum"X"_"i"` = Total f “n” values included in the sample X1.

iii. Find the mean `(bar"X")` of the sample means 

`bar"X" = (sumbar"X")/"Number of samples"`

Where `sumbar"X"` = Total of all the sample means.

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Statistical Quality Control (SQC)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Applied Statistics - Exercise 9.3 [पृष्ठ २२६]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 9 Applied Statistics
Exercise 9.3 | Q 9 | पृष्ठ २२६

संबंधित प्रश्न

Mention the types of causes for variation in a production process


Define chance cause


What do you mean by product control?


Write the control limits for the mean chart


The following data show the values of sample mean `(bar"X")` and its range (R) for the samples of size five each. Calculate the values for control limits for mean, range chart and determine whether the process is in control.

Sample Number 1 2 3 4 5 6 7 8 9 10
Mean 11.2 11.8 10.8 11.6 11.0 9.6 10.4 9.6 10.6 10.0
Range 7 4 8 5 7 4 8 4 7 9

(conversion factors for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)


A quality control inspector has taken ten samples of size four packets each from a potato chips company. The contents of the sample are given below, Calculate the control limits for mean and range chart.

Sample Number Observations
1 2 3 4
1 12.5 12.3 12.6 12.7
2 12.8 12.4 12.4 12.8
3 12.1 12.6 12.5 12.4
4 12.2 12.6 12.5 12.3
5 12.4 12.5 12.5 12.5
6 12.3 12.4 12.6 12.6
7 12.6 12.7 12.5 12.8
8 12.4 12.3 12.6 12.5
9 12.6 12.5 12.3 12.6
10 12.1 12.7 12.5 12.8

(Given for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)


In a certain bottling industry the quality control inspector recorded the weight of each of the 5 bottles selected at random during each hour of four hours in the morning.

Time Weight in ml
8:00 AM 43 41 42 43 41
9:00 AM 40 39 40 39 44
10:00 AM 42 42 43 38 40
11:00 AM 39 43 40 39 42

Choose the correct alternative:

Variations due to natural disorder is known as


Choose the correct alternative:

A typical control charts consists of


Choose the correct alternative:

The upper control limit for `bar"X"` chart is given by


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