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Define Capacitance of a Capacitor and Its Si Unit.

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प्रश्न

Define the capacitance of a capacitor and its SI unit.

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उत्तर

Capacitance

Capacitor is a device which is used to store charge. The capacity of a capacitor to store charge is called capacitance.

`C= "Q"/"V"`

SI unit of capacitor is farad.

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2018-2019 (March) Set 1

संबंधित प्रश्न

Draw a neat labelled diagram of a parallel plate capacitor completely filled with dielectric.


Define the capacitance of a capacitor. Obtain the expression for the capacitance of a parallel plate capacitor in vacuum in terms of plate area A and separation d between the plates.


A slab of material of dielectric constant K has the same area as that of the plates of a parallel plate capacitor but has the thickness d/2, where d is the separation between the plates. Find out the expression for its capacitance when the slab is inserted between the plates of the capacitor. 


A slab of material of dielectric constant K has the same area as that of the plates of a parallel plate capacitor but has the thickness d/3, where d is the separation between the plates. Find out the expression for its capacitance when the slab is inserted between the plates of the capacitor.


A parallel-plate capacitor is charged to a potential difference V by a dc source. The capacitor is then disconnected from the source. If the distance between the plates is doubled, state with reason how the following change:

(i) electric field between the plates

(ii) capacitance, and

(iii) energy stored in the capacitor


A parallel plate air condenser has a capacity of 20µF. What will be a new capacity if:

1) the distance between the two plates is doubled?

2) a marble slab of dielectric constant 8 is introduced between the two plates?


Answer the following question.
Describe briefly the process of transferring the charge between the two plates of a parallel plate capacitor when connected to a battery. Derive an expression for the energy stored in a capacitor.


Solve the following question.
A parallel plate capacitor is charged by a battery to a potential difference V. It is disconnected from the battery and then connected to another uncharged capacitor of the same capacitance. Calculate the ratio of the energy stored in the combination to the initial energy on the single capacitor.   


For a one dimensional electric field, the correct relation of E and potential V is _________.


In a parallel plate capacitor, the capacity increases if ______.


Two identical capacitors are joined in parallel, charged to a potential V, separated and then connected in series, the positive plate of one is connected to the negative of the other. Which of the following is true?


A parallel plate capacitor is connected to a battery as shown in figure. Consider two situations:

  1. Key K is kept closed and plates of capacitors are moved apart using insulating handle.
  2. Key K is opened and plates of capacitors are moved apart using insulating handle.

Choose the correct option(s).

  1. In A: Q remains same but C changes.
  2. In B: V remains same but C changes.
  3. In A: V remains same and hence Q changes.
  4. In B: Q remains same and hence V changes.

A parallel plate capacitor filled with a medium of dielectric constant 10, is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant 15. Then the energy of capacitor will  ______.


What is a capacitor that consists of two large, parallel, conducting plates separated by a small distance called?


For two plates separated by distance \[d\], what is the capacitance of a parallel plate capacitor without a dielectric medium?


What is the capacitance of a parallel plate capacitor with a dielectric medium of dielectric constant \[K\]?


What is the surface charge density \[\sigma\] on a plate carrying charge \[Q\] over area \[A\]?


For a large sheet of charge, what is the electric field due to each plate in terms of surface charge density \[\sigma\]?


What is the effect of increasing plate area \[A\] on capacitance, and why?


What is the effect of inserting a dielectric with \[K>1\] between the plates?


When a dielectric slab of dielectric constant \[K\] is inserted between the plates, what is the electric field \[E'\] due to polarisation of the dielectric?


When the electric field is reduced to \[E'=\frac{E}{K}\] by a dielectric, what happens to potential difference and capacitance?


For the same voltage, what change allows more charge to be stored and more energy to be stored in the capacitor?


In electronic circuits, what are filters and oscillators used for?


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