Advertisements
Advertisements
प्रश्न
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
Advertisements
उत्तर
Steps of Construction :
(i) Draw a line segment PQ = 6 cm.
(ii) At P draw rays making an angle of 45° and at Q, making an angle of 60°, intersecting each other at R.
(iii) Draw the bisectors of ∠P and ∠Q intersecting each other at I.
(iv) From I, draw IL ⊥ PQ.
(v) With centre I and radius IL, draw a circle which touches the sides of Δ PQR internally. This is the required incircle whose I is incentre.
APPEARS IN
संबंधित प्रश्न
Construct a ∆ABC such that:
CB = 6.5 cm, CA = 4.2 cm and BA = 51 cm
Construct a ∆ABC such that:
BC = 4 cm, AC = 5 cm and AB = 3.5 cm
Construct a ∆ ABC such that:
AB = 7 cm, BC = 5 cm and ∠ABC = 60°
Construct a ∆ ABC such that:
BC = 6 cm, AC = 5.7 cm and ∠ACB = 75°
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
