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प्रश्न
Construct a ∆ABC such that:
AB = 6 cm, BC = 4 cm and CA = 5.5 cm
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उत्तर
Steps of Construction :
(i) Draw a line segment BC = 4 cm.
(ii) With centre B and radius 6 cm draw an arc.
(iii) With centre C and radius 5.5 cm, draw another arc intersecting the First are at A.
(iv) Join AB and AC.
∆ABC is the required triangle.
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संबंधित प्रश्न
Construct a ∆ABC such that:
BC = 4 cm, AC = 5 cm and AB = 3.5 cm
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PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Construct an isosceles Δ ABC such that:
Base BC = 4 cm and base angle = 30°. Measure the other two sides of the triangle.
Construct an isosceles Δ ABC such that:
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Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle.
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