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प्रश्न
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
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उत्तर
Steps of Construction :
(i) Draw a line segment MN = 5.8 cm.
(ii) At M and N, draw two rays making an angle of 30° each which intersect each other at P.
(iii) Now draw the angle bisectors of ∠M and ∠N which intersects each other at I.
(iv) From I, draw the perpendicular IL on MN.
(v) With centre I and radius IL, draw a circle which touches the sides of the Δ PMN internally.
On measuring the required incircle and its radius is 0.6 cm.
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संबंधित प्रश्न
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AB = 7 cm, BC = 5 cm and ∠ABC = 60°
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Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
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One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
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