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प्रश्न
Construct an isosceles Δ ABC such that:
Base AC = 5 cm and base angle = 75°. Measure the other two sides of the triangle.
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उत्तर
Steps of Construction:
We know that the base angles of an isosceles triangle are equal.
(i) Draw a line segment AC = 5cm.
(ii) At A and C, draw rays making an angle of 75° each which intersects each other at B.
∆ ABC is the required triangle.
On measuring the equal sides, each is 9.3 cm in length.
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संबंधित प्रश्न
Construct a ∆ABC such that:
AB = 6 cm, BC = 4 cm and CA = 5.5 cm
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°
Construct a ∆ PQR such that :
PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Construct an isosceles Δ ABC such that:
Base BC = 4 cm and base angle = 30°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct a ∆ ABC such that AB = 6 cm, BC = 5.6 cm and CA = 6.5 cm. Inscribe a circle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
