Advertisements
Advertisements
प्रश्न
Construct a ∆ PQR such that :
PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Advertisements
उत्तर
Steps of Construction:
(i) Draw a line segment PQ = 6 cm.
(ii) At P, draw a ray making an angle of 45°
(iii) At Q, draw another ray making an angle of 60° which intersects the first ray at R.
∆ PQR is the required triangle. On measuring ∠R, it is 75°.
APPEARS IN
संबंधित प्रश्न
Construct a ∆ ABC such that:
AB = 7 cm, BC = 5 cm and ∠ABC = 60°
Construct an isosceles Δ ABC such that:
Base BC = 4 cm and base angle = 30°. Measure the other two sides of the triangle.
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Construct an isosceles Δ ABC such that:
Base AC = 5 cm and base angle = 75°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an isosceles ∆ ABC such that:
BC = AB = 5.8 cm and ZB = 30°. Measure ∠A and ∠C.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
