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प्रश्न
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
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उत्तर
Steps of Construction :
(i) Draw a line segment PQ = 6 cm.
(ii) At P draw rays making an angle of 45° and at Q, making an angle of 60°, intersecting each other at R.
(iii) Draw the bisectors of ∠P and ∠Q intersecting each other at I.
(iv) From I, draw IL ⊥ PQ.
(v) With centre I and radius IL, draw a circle which touches the sides of Δ PQR internally. This is the required incircle whose I is incentre.
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संबंधित प्रश्न
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