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प्रश्न
Construct an equilateral ∆ DEF whose one side is 5.5 cm. Construct an incircle to this triangle.
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उत्तर
Steps of Construction :
(i) Draw a line segment BC = 5.5 cm.
(ii) With centres B and C and radius 5.5 cm each draw two arcs intersecting each other at A.
(iii) Join AB and AC.
(iv) Draw the perpendicular bisectors of ∠B and ∠C intersecting each other at I.
(v) From I, draw IL ⊥ BC
(vi) With centre I and radius IL, draw a circle which touches the sides of the Δ ABC internally.
This is the required incircle.
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संबंधित प्रश्न
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°
Construct a ∆ PQR such that:
QR = 4.4 cm, ∠R = 30° and ∠Q = 75°. Measure PQ and PR.
Construct a ∆ PQR such that:
PR = 5.8 cm, ∠P = 60° and ∠R = 45°. Measure ∠Q and verify it by calculations
Construct an isosceles Δ ABC such that:
Base BC = 4 cm and base angle = 30°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Construct a ∆ ABC such that AB = 6 cm, BC = 5.6 cm and CA = 6.5 cm. Inscribe a circle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
