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प्रश्न
Consider the carbon compounds having following molecular formula:
(i) C3H6 (ii) C3H8 (iii) C4H6 (iv) C6H6 (v) C6H12
- State the number of double covalent bonds present in C3H6.
- Write the formula of first member of the homologous series to which the carbon compound C4H6 belongs.
- Which one of the above compounds forms a ring structure of carbon atoms?
- Identify, which of the above compounds, is a member of alkane series.
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उत्तर
(a) Only 1 double covalent bond is present, other is a triple covalent bond.
(b) C4H6 is an alkyne, The alkynes are a group of chemical compounds with carbon and hydrogen at least one triple bond. With a general molecular formula of Cn H2n-2, where n is any integer higher than 1, the group of compounds is a homologous series.
The first member of this homologous series is ethyne (C2H2). \[\ce{H-C=C-H}\]
(c) C6H6 (Benzene) will form the ring. The structure features triple-altemate double bonds and a six-carbon ring, which is symbolised by a hexagon.
(d) C3H8 is an alkane as it has each carbon bonded to four other atoms through single covalent bonds and follow general formula Cn H2n+2.
संबंधित प्रश्न
Write the next homologue of the following: C2H4
Write the molecular formula of first two members of homologous series having functional group -Cl.
Give the molecular formula of one homologue of the following:
C3H6
What is the difference in the molecular formula of any two adjacent homologues in terms of molecular mass?
Complete the correlation:
Alkene : C = C :: Alkyne: _______.
The general molecular formula for the homologous series of alkynes is _______.
Complete the following table for homologous series of alcohols.
| Name | Molecular formula | Condensed structural formula | Number of carbon atom | Number of -CH2- units | Boiling point °C |
| Methanol | CH4O | CH3-OH | 1 | 1 | 63 |
| Ethanol | C2H6O | CH3–CH2-OH | 2 | 2 | 78 |
| Propanol | C3H8O | CH3–CH2–CH2-OH | ______ | ______ | 97 |
| Butanol | C4H10O | CH3–CH2–CH2–CH2–OH | ______ | ______ | 118 |
A carbon compound ‘A’ having melting point 156K and boiling point 351K, with molecular formula C2H6O is soluble in water in all proportions.
- Identify ‘A’ and draw its electron dot structure.
- Give the molecular formulae of any two homologues of ‘A’.
Consider the carbon compounds having following molecular formula:
(i) C2H2 (ii) C2H5 (iii) C3H7OH (iv) C2H6COOH (v) CH3CHO
- Identify which one of the above compounds, is a member of aldehyde series.
- Write the general formula of the series to which compound C2H2 belongs.
- Which one of the above compounds has triple bonds between carbon-carbon atoms?
- Write the molecular formula of the first member of the homologous series to which the compound C3H7OH belongs.
Name the third homologue of alcohols.
