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Classify the Following Functions as Injection, Surjection Or Bijection : F : Q → Q, Defined By F(X) = X3 + 1

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प्रश्न

Classify the following function as injection, surjection or bijection :

f : Q → Q, defined by f(x) = x3 + 1

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उत्तर

f : Q → Q, defined by f(x) = x3 + 1

Injection test :
Let x and y be any two elements in the domain (Q), such that f(x) = f(y).

f(x) = f(y)

x3+1 = y3+ 1

x3 = y3

x = y

So, f is an injection .
Surjection test:

Let y be any element in the co-domain (Q), such that f(x) = y for some element x in Q(domain).

f(x) = y

x3+ 1 = y

`x = 3sqrt(y-1) ,` which may not be in Q.

For example, if y= 8,

x3+ 1 =  8

 x3= 7

 `x = 3sqrt7,`which is not in Q.

So, f is not a surjection and f is not a bijection.

So, f is a surjection and f is a bijection.

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अध्याय 2: Functions - Exercise 2.1 [पृष्ठ ३१]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 2 Functions
Exercise 2.1 | Q 5.13 | पृष्ठ ३१

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