Advertisements
Advertisements
प्रश्न
Calculate the change in momentum of a body weighing 5 kg when its velocity decreases from 20 m/s to 0.20 m/s.
Advertisements
उत्तर
For example,
Given that:
mass, m = 5 kg
velocity, v1 = 20 m/s
Therefore, momentum of a body moving with velocity v1, p1 = m × v1
= 5 × 20 = 100 kg.m/s
Now,
mass, m = 5 kg
velocity, v2 = 0.20 m/s
Therefore, momentum of a body moving with velocity v1, p2 = m × v1
= 5 × 0.20 = 1 kg.m/s
Change in the momentum of a body = p1 − p2
= 100 − 1
= 99 kg.m/s
APPEARS IN
संबंधित प्रश्न
A nucleus is at rest in the laboratory frame of reference. Show that if it disintegrates into two smaller nuclei the products must move in opposite directions.
Figure shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s–2. What is the net force on the man? If the coefficient of static friction between the man’s shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt? (Mass of the man = 65 kg.)
Explain why, it is easier to stop a tennis ball than a cricket ball moving with the same speed.
Define momentum of a body. On what factors does the momentum of a body depend ?
A 10 g bullet travelling at 200 m/s strikes and remains embedded in a 2 kg target which is originally at rest but free to move. At what speed does the target move off ?
The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s.
(a) What is the momentum before the force acts ?
(b) What is the momentum after the force acts ?
(c) What is the gain in momentum per second ?
(d) What is the value of the force ?
A gun of mass 3 kg fires a bullet of mass 30 g. The bullet takes 0.003 s to move through the barrel of the gun and acquires a velocity of 100 m/s. Calculate:
- the velocity with which the gin recoils.
- the force exerted on gunman due to recoil of the gun
The rockets work on the principle of conservation of :
A vessel at rest explodes into three pieces. Two pieces having equal masses fly-off perpendicular to one another with the same velocity 30 meter per second. The third piece has three times mass of each of other piece. The magnitude and direction of the velocity of the third piece will be
A girl riding a bicycle along a straight road with a speed of 5 ms–1 throws a stone of mass 0.5 kg which has a speed of 15 ms–1 with respect to the ground along her direction of motion. The mass of the girl and bicycle is 50 kg. Does the speed of the bicycle change after the stone is thrown? What is the change in speed, if so?
