Advertisements
Advertisements
प्रश्न
Arrange the sides of the following triangles in an ascending order:
ΔDEF, ∠D = 38°, ∠E = 58°.
Advertisements
उत्तर
In ΔDEF,
∠D + ∠E + ∠F = 180°
38° + 58° + ∠F = 180°
96° + ∠F = 180°
∠F = 180° - 96°
∠F = 84°
Hence, ∠D = 38°, ∠E = 58°, ∠F = 84°
38° < 58° < 84°
Hence, ascending order of the angles in the
given triangle is ∠D < ∠E < ∠F.
Hence, ascending order of sides in triangle
EF, DF, DE.
संबंधित प्रश्न
From the following figure, prove that: AB > CD.

Arrange the sides of ∆BOC in descending order of their lengths. BO and CO are bisectors of angles ABC and ACB respectively.

D is a point in side BC of triangle ABC. If AD > AC, show that AB > AC.
In the following figure, ∠BAC = 60o and ∠ABC = 65o.

Prove that:
(i) CF > AF
(ii) DC > DF
In the following figure ; AC = CD; ∠BAD = 110o and ∠ACB = 74o.
Prove that: BC > CD.
“Caste inequalities are still prevalent in India.” Examine the statement.
Name the greatest and the smallest sides in the following triangles:
ΔABC, ∠ = 56°, ∠B = 64° and ∠C = 60°.
Arrange the sides of the following triangles in an ascending order:
ΔABC, ∠A = 45°, ∠B = 65°.
In the given figure, ∠QPR = 50° and ∠PQR = 60°. Show that : PN < RN
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that PT < QT
