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प्रश्न
Arrange the following.
Increasing order of basic strength C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2.
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उत्तर
Due to the delocalization of the lone pair of electrons of the N-atom over the benzene ring, all aromatic amines are less basic than alkylamines i.e., CH3NH2. The presence of electron-donating groups (– CH3) on the N-atom increases the basicity of substituted aniline with respect to C6H5NH2.
In (C6H5)NH2, the lone pair of electrons on the N-atom is delocalized over two benzene rings instead of one in C6H5NH2, therefore (C6H5)NH2 is much less basic than C6H5NH2. Combining all the three trends together, the basic strength of the four amines increasing in order.
(C6H5)NH2 < (C2H5)2NH < C6H5N(CH3)2 < CH3NH2
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संबंधित प्रश्न
Choose the most correct option.
Carbylamine test is given by ____________.
What are amines?
When aniline reacts with acetic anhydride the product formed is ____________.
Write a short note on the following.
Schotten-Baumann reaction
Account for the following.
Ethylamine is soluble in water whereas aniline is not.
The following amine can be classified as:
The reaction of NHO2 with 'A' gives quartering ammonium salt. A is which of the following?
Classify the following amine as primary, secondary or tertiary:
Classify the following amine as primary, secondary or tertiary:
(C2H5)2CHNH2
Assertion A: Aniline on nitration yields ortho, meta and para nitro derivatives of aniline.
Reason R: Nitrating mixture is a storng acidic mixture.
In the light of the above statements, choose the correct answer from the options given below:
