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प्रश्न
Arrange the following.
Increasing order of basic strength C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2.
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उत्तर
Due to the delocalization of the lone pair of electrons of the N-atom over the benzene ring, all aromatic amines are less basic than alkylamines i.e., CH3NH2. The presence of electron-donating groups (– CH3) on the N-atom increases the basicity of substituted aniline with respect to C6H5NH2.
In (C6H5)NH2, the lone pair of electrons on the N-atom is delocalized over two benzene rings instead of one in C6H5NH2, therefore (C6H5)NH2 is much less basic than C6H5NH2. Combining all the three trends together, the basic strength of the four amines increasing in order.
(C6H5)NH2 < (C2H5)2NH < C6H5N(CH3)2 < CH3NH2
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संबंधित प्रश्न
Give reasons for the following:
CH3NH2 is more basis than C6H5NH2.
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IUPAC name for the amine is:
\[\begin{array}{cc}
\phantom{.}\ce{CH3}\\
|\phantom{..}\\
\ce{CH3 - N - C - CH2 - CH3}\\
\phantom{.}|\phantom{.....}|\phantom{........}\\
\phantom{}\ce{CH3}\phantom{..}\ce{C2H5}\phantom{....}
\end{array}\]
Write a short note on the following.
Ammonolysis
Arrange the following.
In increasing order of boiling point C6H5OH, (CH3)2NH, C2H5NH2.
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