Advertisements
Advertisements
प्रश्न
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is ______.

विकल्प
20 cm
15 cm
10 cm
5 cm
Advertisements
उत्तर
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is 20 cm.
Explanation:

We know that, area of triangle = `1/2` × base × height
From the question, it is given that, area of triangle PQR = 100 cm2
Height of the triangle = 10 cm = altitude
Therefore, area of triangle = `1/2` × base × height
100 = `1/2` × PR × 10
PR = `(100 xx 2)/10`
PR = `200/10`
PR = 20 cm
APPEARS IN
संबंधित प्रश्न
If the points A(−2, 1), B(a, b) and C(4, −1) are collinear and a − b = 1, find the values of a and b.
Find the area of a triangle with vertices at the point given in the following:
(−2, −3), (3, 2), (−1, −8)
Find the area of the quadrilaterals, the coordinates of whose vertices are
(−3, 2), (5, 4), (7, −6) and (−5, −4)
The vertices of ΔABC are (−2, 1), (5, 4) and (2, −3) respectively. Find the area of the triangle and the length of the altitude through A.
The point A divides the join of P (−5, 1) and Q(3, 5) in the ratio k:1. Find the two values of k for which the area of ΔABC where B is (1, 5) and C(7, −2) is equal to 2 units.
Prove that the points A(2, 4), B(2, 6) and `C(2 + sqrt(3), 5)` are the vertices of an equilateral triangle.
Show that the ∆ABC is an isosceles triangle if the determinant
Δ = `[(1, 1, 1),(1 + cos"A", 1 + cos"B", 1 + cos"C"),(cos^2"A" + cos"A", cos^2"B" + cos"B", cos^2"C" + cos"C")]` = 0
The area of a triangle with base 4 cm and height 6 cm is 24 cm2.
Find the missing value:
| Base | Height | Area of parallelogram |
| ______ | 15 cm | 154.5 cm2 |
The area of a triangle with vertices A, B, C is given by ______.
