Advertisements
Advertisements
प्रश्न
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is ______.
पर्याय
20 cm
15 cm
10 cm
5 cm
Advertisements
उत्तर
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is 20 cm.
Explanation:
We know that, area of triangle = `1/2` × base × height
From the question, it is given that, area of triangle PQR = 100 cm2
Height of the triangle = 10 cm = altitude
Therefore, area of triangle = `1/2` × base × height
100 = `1/2` × PR × 10
PR = `(100 xx 2)/10`
PR = `200/10`
PR = 20 cm
APPEARS IN
संबंधित प्रश्न
If the points A(−2, 1), B(a, b) and C(4, −1) are collinear and a − b = 1, find the values of a and b.
Prove that the points (2, – 2), (–3, 8) and (–1, 4) are collinear
Find values of k if area of triangle is 4 sq. units and vertices are (−2, 0), (0, 4), (0, k).
Find the area of the quadrilaterals, the coordinates of whose vertices are (–3, 2), (5, 4), (7, –6) and (–5, –4).
Prove that the points (a, 0), (0, b) and (1, 1) are collinear if `1/a+1/b=1`
Four points A (6, 3), B (–3, 5), C (4, –2) and D (x, 3x) are given in such a way that `(ΔDBC)/(ΔABC) = 1/2`, find x.
If the coordinates of the mid-points of the sides of a triangle are (1, 1), (2, —3) and (3, 4), find the vertices of the triangle.
Show that the following points are collinear:
A(5, 1), B(1, –1) and C(11, 4)
Ratio of the area of ∆WXY to the area of ∆WZY is 3 : 4 (see figure). If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.
Area of a triangle PQR right-angled at Q is 60 cm2 (see figure). If the smallest side is 8 cm long, find the length of the other two sides.
