Advertisements
Advertisements
प्रश्न
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is ______.

पर्याय
20 cm
15 cm
10 cm
5 cm
Advertisements
उत्तर
Area of triangle PQR is 100 cm2 (see figure). If altitude QT is 10 cm, then its base PR is 20 cm.
Explanation:

We know that, area of triangle = `1/2` × base × height
From the question, it is given that, area of triangle PQR = 100 cm2
Height of the triangle = 10 cm = altitude
Therefore, area of triangle = `1/2` × base × height
100 = `1/2` × PR × 10
PR = `(100 xx 2)/10`
PR = `200/10`
PR = 20 cm
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the points A(k + 1, 2k), B(3k, 2k + 3) and (5k – 1, 5k) are collinear.
In Fig. 8, the vertices of ΔABC are A(4, 6), B(1, 5) and C(7, 2). A line-segment DE is drawn to intersect the sides AB and AC at D and E respectively such that `(AD)/(AB)=(AE)/(AC)=1/3 `Calculate th area of ADE and compare it with area of ΔABCe.

Prove that the area of a triangle with vertices (t, t −2), (t + 2, t + 2) and (t + 3, t) is independent of t.
If P(–5, –3), Q(–4, –6), R(2, –3) and S(1, 2) are the vertices of a quadrilateral PQRS, find its area.
Prove that the points (a, b), (a1, b1) and (a −a1, b −b1) are collinear if ab1 = a1b.
If the points A(1, 2), O(0, 0) and C(a, b) are collinear, then ______.
Find the coordinates of the point Q on the x-axis which lies on the perpendicular bisector of the line segment joining the points A(–5, –2) and B(4, –2). Name the type of triangle formed by the points Q, A and B.
Find the area of the trapezium PQRS with height PQ given in the following figure.

In the following figure, if PR = 12 cm, QR = 6 cm and PL = 8 cm, then QM is ______.

Find the missing value:
| Base | Height | Area of Triangle |
| 22 cm | ______ | 170.5 cm2 |
