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प्रश्न
Area of a triangle = `1/2` base × ______.
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उत्तर
Area of a triangle = `1/2` base × height.
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संबंधित प्रश्न
A(4, - 6), B(3,- 2) and C(5, 2) are the vertices of a 8 ABC and AD is its median. Prove that the median AD divides Δ ABC into two triangles of equal areas.
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Find the area of the quadrilaterals, the coordinates of whose vertices are
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Prove that (2, –2) (–2, 1) and (5, 2) are the vertices of a right-angled triangle. Find the area of the triangle and the length of the hypotenuse.
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(1, −1), (2, 1) and (4, 5)
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If a ≠ b ≠ c, prove that the points (a, a2), (b, b2), (c, c2) can never be collinear.
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If the co-ordinates of the vertices of an equilateral triangle with sides of length ‘a’ are (x1, y1), (x2, y2), (x3, y3), then `|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|^2 = (3"a"^4)/4`
Let `Delta = abs (("x", "y", "z"),("x"^2, "y"^2, "z"^2),("x"^3, "y"^3, "z"^3)),` then the value of `Delta` is ____________.
