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प्रश्न
Area of a triangle = `1/2` base × ______.
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उत्तर
Area of a triangle = `1/2` base × height.
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संबंधित प्रश्न
In Fig. 6, ABC is a triangle coordinates of whose vertex A are (0, −1). D and E respectively are the mid-points of the sides AB and AC and their coordinates are (1, 0) and (0, 1) respectively. If F is the mid-point of BC, find the areas of ∆ABC and ∆DEF.
If the points A(−2, 1), B(a, b) and C(4, −1) are collinear and a − b = 1, find the values of a and b.
For what value of x will the points (x, –1), (2, 1) and (4, 5) lie on a line ?
Find the area of the triangle whose vertices are: (–5, –1), (3, –5), (5, 2)
Find values of k if area of triangle is 4 sq. units and vertices are (k, 0), (4, 0), (0, 2).
Find the area of ΔABC with A(1, –4) and midpoints of sides through A being (2, –1) and (0, –1).
Find the value of y for which the points A(–3, 9), B(2, y) and C(4, –5) are collinear.
If the sides of a triangle are 3 cm, 4 cm and 5 cm, then the area is
The area of ∆ABC is 8 cm2 in which AB = AC = 4 cm and ∠A = 90º.
Ratio of the area of ∆WXY to the area of ∆WZY is 3 : 4 (see figure). If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.
