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प्रश्न
Area of a triangle = `1/2` base × ______.
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उत्तर
Area of a triangle = `1/2` base × height.
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संबंधित प्रश्न
Prove that the points (2, – 2), (–3, 8) and (–1, 4) are collinear
Find the area of a triangle with vertices at the point given in the following:
(2, 7), (1, 1), (10, 8)
Find the area of the quadrilaterals, the coordinates of whose vertices are (–3, 2), (5, 4), (7, –6) and (–5, –4).
The four vertices of a quadrilateral are (1, 2), (−5, 6), (7, −4) and (k, −2) taken in order. If the area of the quadrilateral is zero, find the value of k.
If the coordinates of the mid-points of the sides of a triangle are (1, 1), (2, —3) and (3, 4), find the vertices of the triangle.
If the coordinates of the mid-points of the sides of a triangle are (3, 4), (4, 6) and (5, 7), find its vertices.
For what values of k are the points A(8, 1), B(3, –2k) and C(k, –5) collinear?
If the points P(–3, 9), Q(a, b) and R(4, –5) are collinear and a + b = 1, find the values of a and b.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
If the points (a1, b1), (a2, b2) and(a1 + a2, b1 + b2) are collinear, then ____________.
