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प्रश्न
Find the area of a triangle with vertices at the point given in the following:
(1, 0), (6, 0), (4, 3)
बेरीज
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उत्तर
Area of the triangle passing through the vertices (x1, y1), (x2, y2), (x3, y3),
Δ = `1/2 |(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)|`
The area of triangle is given by,
Δ = `1/2 abs((1,0,1),(6,0,1),(4,3,1))`
= `1/2 [1 (0 - 3) - 0 (6 - 4) + 1 (18 - 0)]`
= `1/2 [-3 + 18]`
= `15/2`
= 7.5 sq. units
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