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Find the area of a triangle with vertices at the point given in the following: (1, 0), (6, 0), (4, 3) - Mathematics

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प्रश्न

Find the area of a triangle with vertices at the point given in the following:

(1, 0), (6, 0), (4, 3)

योग
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उत्तर

Area of ​​the triangle passing through the vertices (x1, y1), (x2, y2), (x3, y3),

Δ = `1/2 |(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)|`

The area of triangle is given by,

Δ = `1/2 abs((1,0,1),(6,0,1),(4,3,1))`

= `1/2 [1 (0 - 3) - 0 (6 - 4) + 1 (18 - 0)]`

= `1/2 [-3 + 18]`

= `15/2`

= 7.5 sq. units

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अध्याय 4: Determinants - Exercise 4.3 [पृष्ठ १२२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 4 Determinants
Exercise 4.3 | Q 1.1 | पृष्ठ १२२
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