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A Solid Metallic Sphere of Diameter 21 Cm is Melted and Recast into a Number of Smaller Cones, Each of Diameter 3.5 Cm and Height 3 Cm. Find the Number of Cones So Formed.

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प्रश्न

A solid metallic sphere of diameter 21 cm is melted and recast into a number of smaller cones, each of diameter 3.5 cm and height 3 cm. Find the number of cones so formed.

योग
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उत्तर

Diameter of sphere = 21 cm

Radius of sphere =`21/2` cm

Volume of sphere `= 4/3 pir^3 = (4xx21xx21xx21xx21pi)/(3xx2xx2xx2)= (21xx21xx21pi)/(3xx2)    "cm"^3`

Diameter of the cone = 3.5 cm

Radius of the cone `= 3.5/2 = 7/4  "cm"`

Height = 3 cm

Volume of each cone` = 1/3pir^2h xx 1/3pixx3xx(7/4)^2 = (7/4)^2 pi  "cm"^3 `

`"Total number of cones"= "Volume of sphere"/"Volume of a cone" = ((21xx21xx21pi)/(3xx2))/((7/4)^2pi) = (21xx21xx21xxpixx4xx4)/3xx2xxpixx)`

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अध्याय 17: Volumes and Surface Areas of Solids - Exercise 19B [पृष्ठ ८९८]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 17 Volumes and Surface Areas of Solids
Exercise 19B | Q 9 | पृष्ठ ८९८

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