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A Rocket is in the Form of a Circular Cylinder Closed at the Lower End and a Cone of the Same Radius is Attached to the Top. the Radius of the Cylinder is 2.5 M, Its Height is 21 M and

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प्रश्न

A rocket is in the form of a circular cylinder closed at the lower end and a cone of the same radius is attached to the top. The radius of the cylinder is 2.5 m, its height is 21 m and the slant height of the cone is 8 m. Calculate the total surface area of the rocket.

योग
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उत्तर

Radius of the cylinder = 2.5 m
Height of the cylinder = 21 m 

Curved surface area of the cylinder `= 2pirh = 2xx22/7xx2.5xx21=330` m2

Radius of the cone = 2.5 m

Slant height of the cone = 8 m

Curved surface area of the cone `= pirl = 22/7 xx2.5xx8 = 62.86` m2

Area of circular base = `pir^2 = 22/7xx2.5xx2.5xx=19.643`

∴ Total surface area of rocket = 330 + 62.86 + 19.643 m

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अध्याय 17: Volumes and Surface Areas of Solids - Exercise 19A [पृष्ठ ८७५]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 17 Volumes and Surface Areas of Solids
Exercise 19A | Q 12 | पृष्ठ ८७५

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