Question

Find the volume of a solid in the form of a right circular cylinder with hemi-spherical ends whose total length is 2.7 m and the diameter of each hemi-spherical end is 0.7 m.

Answer 1

Radius of hemispherical ends = radius of cylinder

`=1/2 xx 0.7`

`=7/20 m`

Total length = 2.7 m.

Height of cylinder

`=2.7 - 2 xx 7/20`

`= 2m`

Volume of two hemispheres

`=2 (2/3 pir^3)`

`=4/3 pir^3`

`=4/3 xx 22/7 xx (7/20)^3`

`=4/3 xx 22 /7 xx (343)/(800)`

` = 0.1797 m^3`

Volume of cylinders

` =pir^2h`

`=22/7 xx (7/20)^2 xx 2`

`=0.77 m^2`

Hence,

Volume of solid = 0.1797+0.77 = 0.95 m³