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Water is Flowing Through a Cylindrical Pipe of Internal Diameter 2 Cm, into a Cylindrical Tank of Base Radius 40 Cm, at the Rate of 0.4 M per Second. Determine the Rise - Mathematics

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प्रश्न

Water is flowing through a cylindrical pipe of internal diameter 2 cm, into a cylindrical tank of base radius 40 cm, at the rate of 0.4 m per second. Determine the rise in level of water in the tank in half an hour.

योग
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उत्तर

We have,

the internal radius of the cylindrical pipe, r = 2/2 = 1 cm and

the base radius of cylindrical tank, R = 40 cm.

Also, the rate of flow, h = 0.4 m/s = 40 cm/s

Let the rise in level of water be H.

Now,

The volume of water flowing out of the cylindrical pipe in 1 sec =πr2h = π × 1 × 1 × 40 = 40π cm3

As,

Volume of water in the cylindrical tank = Volume of standing water in cylindrical pipe

⇒πR2H = 72000π

⇒R^2H = 72000`

⇒ 40 × 40 × H = 7200H

`rArr H = 72000/(40xx40)`

∴ H = 45 cm

So, the rise in level of water in the tank in half an hour is 45 cm.

Disclaimer: The answer given in the textbook is incorrect. The same has been corrected above.

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अध्याय 19: Volume and Surface Area of Solids - Exercise 19B [पृष्ठ ८९९]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 19 Volume and Surface Area of Solids
Exercise 19B | Q 24 | पृष्ठ ८९९

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