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प्रश्न
A rectangle plate of sides a and b is suspended from a ceiling by two parallel string of length L each in Figure . The separation between the string is d. The plate is displaced slightly in its plane keeping the strings tight. Show that it will execute simple harmonic motion. Find the time period.
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उत्तर
Let m is the mass of rectangular plate and x is the displacement of the rectangular plate.
During the oscillation, the centre of mass does not change.
Driving force \[\left( F \right)\] is given as,
F = mgsin θ
Comparing the above equation with F = ma, we get:
\[a = \frac{F}{m} = g\sin\theta\]
For small values of θ, sinθ can be taken as equal to θ.
Thus, the above equation reduces to:
\[a = g\theta = g\left( \frac{x}{L} \right) \left[ \text { Where g and L are constant .} \right]\]
It can be seen from the above equation that, a α x.
Hence, the motion is simple harmonic.
Time period of simple harmonic motion \[\left( T \right)\]is given by,
\[T = 2\pi\sqrt{\frac{\text { displacement }}{\text { Acceleration }}}\]
\[ = 2\pi\sqrt{\frac{x}{gx/L}} = 2\pi\sqrt{\frac{L}{g}}\]
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