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A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is doubled? - Chemistry

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प्रश्न

A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is doubled?

संख्यात्मक
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उत्तर

Reactant → Product

Rate of reaction, R = k [A]2

If the concentration of the reactant is doubled, i.e.,

[A] = 2A, 

Then the rate of the reaction would be R = k[2A]2

= k 4 A2

= 4 kA2

Change in rate of reaction = `"rate of reaction when concentration is doubled"/"rate of reaction originally"`

= `(4 kA^2)/(kA^2)`

= 4 : 1

When the concentration is doubled, the reaction rate increases by a factor of 4.

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अध्याय 3: Chemical Kinetics - Exercises [पृष्ठ ८५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 3 Chemical Kinetics
Exercises | Q 3.6 (i) | पृष्ठ ८५

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