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A person of mass 60 kg wants to lose 5kg by going up and down a 10 m high stairs. Assume he burns twice as much fat while going up than coming down.

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प्रश्न

A person of mass 60 kg wants to lose 5kg by going up and down a 10 m high stairs. Assume he burns twice as much fat while going up than coming down. If 1 kg of fat is burnt on expending 7000 kilo calories, how many times must he go up and down to reduce his weight by 5 kg?

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उत्तर

Given, the height of the stair = h = 10 m

The energy produced by burning 1 kg of fat = 7000 cal

∴ The energy produced by burning 5 kg of fat = 5 × 7000 = 35000 kcal

35 × 106 cal

The energy utilised in going up and down one time

= `mgh + 1/2 mgh`

= `3/2 mgh`

= `3/2 xx 60 xx 10 xx 10`

= 9000 J

= `9000/4.2`

= `3000/1.4` cal

∴ A number of times, the person has to go up and down the stairs

= `(35 xx 10^6)/(3000/1.4)`

= `(35 xx 1.4 xx 10^6)/3000`

= 16.3 × 103 times

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अध्याय 12: Thermodynamics - Exercises [पृष्ठ ८७]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 12 Thermodynamics
Exercises | Q 12.18 | पृष्ठ ८७

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