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A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with acceleration of 0⋅5 m/s2,find work done by the man on the block during the motion.

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प्रश्न

A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of 0⋅5 m/s2, find the work done by the man on the block during the motion.

योग
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उत्तर

Given:

\[\text{ Mass of the block, m = 2 kg } \]
\[\text{ Distance coverd by the man, s = 40 m } \]
\[\text{Acceleration of the man, a = 0 . 5 m} / s^2\]
So, force applied by the man on the box,
 

\[\text{ F = ma } \]

\[ = 2 \times \left( 0 . 5 \right)\]

\[ = 1 N\]

\[\text{ Work done by the man on the block, } W = F \cdot S\]

\[ = 1 \times 40\]

\[ = 40 J\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Work and Energy - Exercise [पृष्ठ १३२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 8 Work and Energy
Exercise | Q 7 | पृष्ठ १३२

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