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प्रश्न
A lady plans to save for her daughter’s marriage. She wishes to accumulate a sum of ₹ 4,64,100 at the end of 4 years. What amount should she invest every year if she gets an interest of 10% p.a. compounded annually? [Given (1.1)4 = 1.4641]
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उत्तर
Given: A = ₹ 4,64,100, n = 4 years, r = 10% p.a.
i = `r/(100) = (10)/(100)` = 0.1
Now, A = `C/i[(1 + i)^n - 1]`
∴ 4,64,100 = `C/(0.1)[(1 + 0.1)^4 - 1]`
∴ 4,64,100 × (0.1) = C[(1.1)4 – 1]
∴ 46,410 = C[1.4641 – 1]
∴ 46,410 = C(0.4641)
∴ C = `(46,410)/(0.4641)`
∴ C = 1,00,000
∴ She must invest ₹ 1,00,000 every year.
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∴ Rate of interest per quarter = `square/4` = 4
⇒ r = 4%
⇒ i = `square/100 = 4/100` = 0.04
n = Number of quarters
= 4 × 1
= `square`
⇒ P' = `(C(1 + i))/i [1 - (1 + i)^-n]`
⇒ P' = `(square(1 + square))/0.04 [1 - (square + 0.04)^-square]`
= `(2000(square))/square [1 - (square)^-4]`
= 50,000`(square)`[1 – 0.8548]
= ₹ 7,550.40
