Advertisements
Advertisements
प्रश्न
A geyser is rated 1500 W, 250 V. This geyser is connected to 250 V mains. Calculate:
- The current drawn,
- The energy consumed in 50 hours, and
- The cost of energy consumed at ₹ 4.20 per kWh.
Advertisements
उत्तर
Given,
Power of geyser, P = 1500 W
Voltage, V = 250 V
- Current, I = `"P"/"V"`
I = `1500/250`
= 6 A - Time, t = 50 h
Energy, E = P × t
= 1500 × 50
= 75000 Wh
= 75 kWh - Cost per unit of energy = Rs 4.20
Cost for 75 kWh of energy = 4.20 × 75
= ₹ 315
APPEARS IN
संबंधित प्रश्न
1 A = _________ mA
- 102
- 103
- 10-3
- 10-6
Choose the correct alternative and rewrite the following sentence.
When the resistance of a conductor increases, the current will ________ increase.
The p.d. across a 3 Ω resistor is 6 V. The current flowing in the resistor will be:
(a) `1/2A`
(b) 1 A
(c) 2 A
(d) 6 A
Which type of circuit, series or parallel, is preferred while connecting a large number of bulbs:
(a) for decorating a hotel building from outside?
Ten bulbs are connected in a series circuit to a power supply line. Ten identical bulbs are connected in a parallel circuit to an identical power supply line.
(a) Which circuit would have the highest voltage across each bulb?
A given wire of resistance 1 Ω is stretched to double its length. What will be its new resistance?
Tell the odd one out. Give a proper explanation.
A current of 0.3 A is flowing through a branch of 6 Ω resistors in a junction as shown in fig. . Calculate the
(a) P.d. across the junction XY,
(b) Current flowing through 9Ω and 24Ω
( c) P.d. across 24 Ω resistor, and
( d) e.m.f. of the cell.

When an electric current is passed, electrons move from:
