Advertisements
Advertisements
प्रश्न
A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m s-1. Find the magnitude of the force.
Advertisements
उत्तर
Mass, m = 2.0 kg i.e. 2 kg
Initial velocity, u = 0
Final velocity, v = 2 m/s
Time, t = 0.1 s
Acceleration = `"Change in velocity"/"time"`
∴ a = `("v" - "u")/"t"`
∴ a = `(2 - 0)/0.1`
∴ a = 20 ms-2.
Force = Mass × Acceleration
⇒ F = 2 × 20
∴ F = 40 N.
APPEARS IN
संबंधित प्रश्न
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
Which force is responsible for the moon revolving round the earth ?
What is the acceleration produced in a freely falling body of mass 10 kg ? (Neglect air resistance)
During a free fall, will heavier objects accelerate more than lighter ones ?
Explain why, if a stone held in our hand is released, it falls towards the earth.
The value of acceleration due to gravity of earth :
Choose one or more correct alternatives.
Which of the forces involved in dragging a heavy object on a smooth, horizontal surface, have the same magnitude?
- The horizontal applied force
- gravitational force
- reaction force in vertical direction
- force of friction
The value of gravitational acceleration at the centre of earth is zero.
Write scientific reason.
When we drop a feather and a stone at the same time from a height the stone reach the earth faster than a feather.
Write acceleration due to gravity value on the surface of Earth.
