Advertisements
Advertisements
प्रश्न
A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m s-1. Find the magnitude of the force.
Advertisements
उत्तर
Mass, m = 2.0 kg i.e. 2 kg
Initial velocity, u = 0
Final velocity, v = 2 m/s
Time, t = 0.1 s
Acceleration = `"Change in velocity"/"time"`
∴ a = `("v" - "u")/"t"`
∴ a = `(2 - 0)/0.1`
∴ a = 20 ms-2.
Force = Mass × Acceleration
⇒ F = 2 × 20
∴ F = 40 N.
APPEARS IN
संबंधित प्रश्न
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
When an object is dropped from a height, it accelerates and falls down. Name the force which accelerates the object.
What is the usual value of the acceleration due to gravity of earth ?
A pressure of 10 Pa acts on an area of 3.0 m2. What is the force acting on the area ? What force will be exerted by the application of same pressure if the area is made one-third ?
A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The retardation produced in car.
How is the acccelaration due to gravity on the surface of the earth realted to its mass and radius ?
What force, in newton, your muscles need to apply to hold a mass of 5 kg in your hand? State the assumption.
State whether the below statement is True or False.
Neglecting air resistance, a body falling freely near the earth's surface has a constant acceleration.
The value of gravitational acceleration (g) is ______.
Calculate the escape velocity on the surface of the moon given the mass and radius of the moon to be 7.34 × 1022 kg and 1.74 × 106 m respectively.
(Given: G = 6.67 × 10-11 Nm2/kg2)
